shout: fixed the lame input buffer allocation
"float (*lamebuf)[2] = g_malloc()" does NOT allocate two float* buffers. The formula is even wrong: it should be applied to LAME's output buffer, not its input buffer. Converted "lamebuf" to the two variables "left" and "right", and allocate them independently with the exact buffer size. Set right=left if mono output is configured.
This commit is contained in:
@@ -133,8 +133,7 @@ static int shout_mp3_encoder_encode(struct shout_data *sd,
|
||||
{
|
||||
const int16_t *src = (const int16_t*)chunk;
|
||||
unsigned int i;
|
||||
int j;
|
||||
float (*lamebuf)[2];
|
||||
float *left, *right;
|
||||
struct shout_buffer *buf = &(sd->buf);
|
||||
unsigned int samples;
|
||||
int bytes = audio_format_sample_size(&sd->audio_format);
|
||||
@@ -142,21 +141,28 @@ static int shout_mp3_encoder_encode(struct shout_data *sd,
|
||||
int bytes_out;
|
||||
|
||||
samples = len / (bytes * sd->audio_format.channels);
|
||||
/* rough estimate, from lame.h */
|
||||
lamebuf = g_malloc(sizeof(float) * (1.25 * samples + 7200));
|
||||
left = g_malloc(sizeof(left[0]) * samples);
|
||||
if (sd->audio_format.channels > 1)
|
||||
right = g_malloc(sizeof(left[0]) * samples);
|
||||
else
|
||||
right = left;
|
||||
|
||||
/* this is for only 16-bit audio */
|
||||
|
||||
for (i = 0; i < samples; i++) {
|
||||
for (j = 0; j < sd->audio_format.channels; j++) {
|
||||
lamebuf[j][i] = *src++;
|
||||
}
|
||||
left[i] = src[0];
|
||||
if (right != left)
|
||||
right[i] = src[1];
|
||||
src += sd->audio_format.channels;
|
||||
}
|
||||
|
||||
bytes_out = lame_encode_buffer_float(ld->gfp, lamebuf[0], lamebuf[1],
|
||||
bytes_out = lame_encode_buffer_float(ld->gfp, left, right,
|
||||
samples, buf->data,
|
||||
sizeof(buf->data) - buf->len);
|
||||
free(lamebuf);
|
||||
|
||||
g_free(left);
|
||||
if (right != left)
|
||||
g_free(right);
|
||||
|
||||
if (0 > bytes_out) {
|
||||
g_warning("error encoding lame buffer for shout\n");
|
||||
|
Reference in New Issue
Block a user