directory: converted isRootDirectory() to an inline function

The function isRootDirectory() is tiny and can be converted to an
inline function.  Don't allow name==NULL.
This commit is contained in:
Max Kellermann 2008-10-08 11:06:44 +02:00
parent e1a4474ad4
commit ba5c9b0375
2 changed files with 10 additions and 6 deletions

View File

@ -101,11 +101,6 @@ void directory_finish(void)
freeDirectory(music_root);
}
int isRootDirectory(const char *name)
{
return (!name || name[0] == '\0' || !strcmp(name, "/"));
}
struct directory *
directory_get_root(void)
{
@ -122,6 +117,8 @@ getSubDirectory(struct directory * directory, const char *name)
char *duplicated;
char *locate;
assert(name != NULL);
if (isRootDirectory(name))
return directory;
@ -148,6 +145,9 @@ getSubDirectory(struct directory * directory, const char *name)
struct directory *
getDirectory(const char *name)
{
if (name == NULL)
return music_root;
return getSubDirectory(music_root, name);
}

View File

@ -46,7 +46,11 @@ void directory_init(void);
void directory_finish(void);
int isRootDirectory(const char *name);
static inline bool
isRootDirectory(const char *name)
{
return name[0] == 0 || (name[0] == '/' && name[1] == 0);
}
struct directory *
directory_get_root(void);