directory: converted isRootDirectory() to an inline function
The function isRootDirectory() is tiny and can be converted to an inline function. Don't allow name==NULL.
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e1a4474ad4
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@ -101,11 +101,6 @@ void directory_finish(void)
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freeDirectory(music_root);
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}
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int isRootDirectory(const char *name)
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{
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return (!name || name[0] == '\0' || !strcmp(name, "/"));
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}
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struct directory *
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directory_get_root(void)
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{
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@ -122,6 +117,8 @@ getSubDirectory(struct directory * directory, const char *name)
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char *duplicated;
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char *locate;
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assert(name != NULL);
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if (isRootDirectory(name))
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return directory;
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@ -148,6 +145,9 @@ getSubDirectory(struct directory * directory, const char *name)
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struct directory *
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getDirectory(const char *name)
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{
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if (name == NULL)
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return music_root;
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return getSubDirectory(music_root, name);
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}
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@ -46,7 +46,11 @@ void directory_init(void);
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void directory_finish(void);
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int isRootDirectory(const char *name);
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static inline bool
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isRootDirectory(const char *name)
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{
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return name[0] == 0 || (name[0] == '/' && name[1] == 0);
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}
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struct directory *
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directory_get_root(void);
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