133 lines
		
	
	
		
			3.7 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
			
		
		
	
	
			133 lines
		
	
	
		
			3.7 KiB
		
	
	
	
		
			C
		
	
	
	
	
	
| /*
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|  * Copyright (c) 1997 - 2000 Kungliga Tekniska Högskolan
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|  * (Royal Institute of Technology, Stockholm, Sweden).
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|  * All rights reserved.
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|  *
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|  * Redistribution and use in source and binary forms, with or without
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|  * modification, are permitted provided that the following conditions
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|  * are met:
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|  *
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|  * 1. Redistributions of source code must retain the above copyright
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|  *    notice, this list of conditions and the following disclaimer.
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|  *
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|  * 2. Redistributions in binary form must reproduce the above copyright
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|  *    notice, this list of conditions and the following disclaimer in the
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|  *    documentation and/or other materials provided with the distribution.
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|  *
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|  * 3. Neither the name of the Institute nor the names of its contributors
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|  *    may be used to endorse or promote products derived from this software
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|  *    without specific prior written permission.
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|  *
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|  * THIS SOFTWARE IS PROVIDED BY THE INSTITUTE AND CONTRIBUTORS ``AS IS'' AND
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|  * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
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|  * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
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|  * ARE DISCLAIMED.  IN NO EVENT SHALL THE INSTITUTE OR CONTRIBUTORS BE LIABLE
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|  * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
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|  * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
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|  * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
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|  * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
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|  * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
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|  * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
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|  * SUCH DAMAGE.
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|  */
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| 
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| #include "kadm5_locl.h"
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| 
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| RCSID("$Id$");
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| 
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| /*
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|  * free all the memory used by (len, keys)
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|  */
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| 
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| void
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| _kadm5_free_keys (krb5_context context,
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| 		  int len, Key *keys)
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| {
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|     hdb_free_keys(context, len, keys);
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| }
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| 
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| /*
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|  * null-ify `len', `keys'
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|  */
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| 
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| void
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| _kadm5_init_keys (Key *keys, int len)
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| {
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|     int i;
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| 
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|     for (i = 0; i < len; ++i) {
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| 	keys[i].mkvno               = NULL;
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| 	keys[i].salt                = NULL;
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| 	keys[i].key.keyvalue.length = 0;
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| 	keys[i].key.keyvalue.data   = NULL;
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|     }
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| }
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| 
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| 
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| /*
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|  * return 1 if any key in `keys1, len1' exists in `keys2, len2'
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|  */
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| static int
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| _kadm5_exists_keys(Key *keys1, int len1, Key *keys2, int len2)
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| {
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|     size_t i, j;
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|     size_t optimize;
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| 
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|     for (i = 0; i < len1; ++i) {
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| 	optimize = 0;
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| 	for (j = 0; j < len2; j++) {
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| 	    if ((keys1[i].salt != NULL && keys2[j].salt == NULL)
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| 		|| (keys1[i].salt == NULL && keys2[j].salt != NULL))
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| 		continue;
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| 
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| 	    if (keys1[i].salt != NULL) {
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| 		if (keys1[i].salt->type != keys2[j].salt->type)
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| 		    continue;
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| 		if (keys1[i].salt->salt.length != keys2[j].salt->salt.length)
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| 		    continue;
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| 		if (memcmp (keys1[i].salt->salt.data, keys2[j].salt->salt.data,
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| 			    keys1[i].salt->salt.length) != 0)
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| 		    continue;
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| 	    }
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| 	    if (keys1[i].key.keytype != keys2[j].key.keytype)
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| 		continue;
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| 	    optimize = 1;
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| 	    if (keys1[i].key.keyvalue.length != keys2[j].key.keyvalue.length)
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| 		continue;
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| 	    if (memcmp (keys1[i].key.keyvalue.data, keys2[j].key.keyvalue.data,
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| 			keys1[i].key.keyvalue.length) != 0)
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| 		continue;
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| 
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| 	    return 1;
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| 	}
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| 
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| 	/*
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| 	 * Optimization: no need to check all of keys1[] if one there
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| 	 * was one key in keys2[] with matching enctype and salt but not
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| 	 * matching key.  Assumption: all keys in keys1[] and keys2[]
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| 	 * are output by string2key.
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| 	 */
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| 	if (optimize)
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| 	    return 0;
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|     }
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|     return 0;
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| }
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| 
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| /*
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|  * return 1 if any key in `keys1, len1' exists in hist_keys
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|  */
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| int
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| _kadm5_exists_keys_hist(Key *keys1, int len1, HDB_Ext_KeySet *hist_keys)
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| {
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|     size_t i;
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| 
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|     for (i = 0; i < hist_keys->len; i++) {
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| 	if (_kadm5_exists_keys(keys1, len1,
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| 			       hist_keys->val[i].keys.val,
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| 			       hist_keys->val[i].keys.len))
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| 	    return 1;
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|     }
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| 
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|     return 0;
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| }
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