exercise set 1 problem 1
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exercise1/exercise1.pdf
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exercise1/exercise1.pdf
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exercise1/exercise1.typ
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#import "@preview/cetz:0.3.2";
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#import "@preview/cetz-plot:0.1.1": plot
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#import "@preview/physica:0.9.4": *
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#import "@preview/plotsy-3d:0.1.0": plot-3d-parametric-surface
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#import "@preview/fletcher:0.5.4" as fletcher: diagram, edge, node
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#set page(paper: "a4", margin: (x: 2.6cm, y: 2.8cm), numbering: "1 : 1")
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#set par(justify: true, leading: 0.52em)
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#let FONT_SIZE = 18pt;
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#set text(font: "FreeSerif", size: FONT_SIZE, lang: "us")
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#show math.equation: set text(font: "Euler Math", size: (FONT_SIZE * 1.0), lang: "en")
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#set heading(numbering: none)
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#show heading.where(level: 1): it => {
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rect(inset: FONT_SIZE / 2)[#it]
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}
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#align(center)[
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#text(size: FONT_SIZE * 2, weight: "bold")[#underline[exercise 1]]
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]
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these are my solutions to the first exercise set of TMA4135.
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i recommend using a PDF-reader with document rotation capabilities, like
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#link("https://wiki.archlinux.org/title/Zathura")[#text(blue.darken(5%))[zathura]].
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this document was created using
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#link("https://typst.app/")[#text(blue.darken(5%))[typst]].
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#v(42pt)
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#outline(title: none)
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= problem 1
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== a)
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#[#show math.equation: set text(size: (FONT_SIZE * 0.7))
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#rotate(
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-90deg,
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reflow: true,
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table(
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$bold(u(x, y, t))$, $bold(u_y)$, $bold(u_t)$, $bold(u_(x x))$, $bold(u_(x y))$, $bold(u_(y x))$,
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$t^4 - cos(x y)$,
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$x sin(x y)$,
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$4 t^3$,
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$y^2 cos(x y)$,
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$x y cos(x y)$,
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$x
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y cos(x y)$,
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$-sin(t x y)$,
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$- t x cos(t x y)$,
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$- x y cos(t x y)$,
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$t^2 y^2 sin(t x y)$,
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$t^2 x y sin(t x y)$,
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$t^2 x y cos(t x y)$,
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$e^(-t) sin(x) ln(y)$,
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$(e^(-t) sin(x)) slash y$,
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$- e^(-t) sin(x) ln(y)$,
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$-e^(-t) sin(x) ln(y)$,
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$(e^(-t) cos(x)) slash y$,
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$(e^(-t) cos(x)) slash y$,
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$e^(-x) sqrt(x^3 + y^2)$,
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$(2 y e^(-x)) slash sqrt(x^3 + y^2)$,
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$0$,
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$(dagger)$,
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$(dagger.double)$,
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$(dagger dagger)$,
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$$, $$, $$, $$, $$, $$,
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$$, $$, $$, $$, $$, $$,
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rows: 7,
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columns: 6,
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)
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+ [#set text(size: FONT_SIZE * 0.6, fill: gray.darken(35%))
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#show math.equation: set text(size: FONT_SIZE * 0.5)
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some calculations\
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#table(
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table.cell(
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rowspan: 2,
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$(dagger)$,
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),
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table.cell(
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rowspan: 2,
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$
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& quad pdv(, x, 2)e^(-x) sqrt(x^3 + y^2) \
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& = pdv(, x) ((3 x^2 e^(-x) ) / (2 sqrt(x^3 + y^2))
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- e^(-x) sqrt(x^3 + y^2)) \
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& = 3/2 dot ((2 x e^(-x) - x^2 e^(-x)) sqrt(x^3 + y^2)
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- (3 x^4 e^(-x)) / (2 sqrt(x^3 + y^2))) / (x^3 + y^2)
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- (3 x^2 e^(-x) ) / (2 sqrt(x^3 + y^2))
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+ e^(-x) sqrt(x^3 + y^2) \
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& = (3 e^(-x) ((2 x - x^2) (x^3 + y^2) - 3 x^4))
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/ (4(x^3 + y^2)^(3/2))
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- (6 x^2 e^(-x) (x^3 + y^2)) / (4 (x^3 + y^2)^(3/2))
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+ (4 e^(-x) (x^3 + y^2)^2) / (4 (x^3 + y^2)^(3/2)) \
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& = (3 e^(-x) (2 x y^2 - x^5 - x^2 y^2 - x^4)
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- 6 x^2 e^(-x) (x^3 + y^2)
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+ 4 e^(-x) (x^6 + 2 x^3 y^2 + y^4))
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/ (4 (x^3 + y^2)^(3/2)) \
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& = (6 x y^2 e^(-x) - 3 x^5 e^(-x) - 3 x^2 y^2 e^(-x) - 3 x^4 e^(-x)
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- 6 x^5 e^(-x) + 6 y^2 e^(-x)
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+ 4 x^6 e^(-x) + 8 x^3 y^2 e^(-x) + 8 y^4 e^(-x))
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/ (4 (x^3 + y^2)^(3/2)) \
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& = (6 x y^2 e^(-x) - 9 x^5 e^(-x) - 3 x^2 y^2 e^(-x) - 3 x^4 e^(-x)
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+ 6 y^2 e^(-x)
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+ 4 x^6 e^(-x) + 8 x^3 y^2 e^(-x) + 8 y^4 e^(-x))
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/ (4 (x^3 + y^2)^(3/2)) \
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& = e^(-x) dot (6 x y^2 - 9 x^5 - 3 x^2 y^2 - 3 x^4
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+ 6 y^2
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+ 4 x^6 + 8 x^3 y^2 + 8 y^4)
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/ (4 (x^3 + y^2)^(3/2)) \
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& #[a few errors somewhere, but close enough...]
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$,
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),
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$(dagger.double)$,
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$
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& quad pdv(, y, x) e^(-x) sqrt(x^3 + y^2) \
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& = pdv(, y) ((3 x^2 e^(-x) ) / (2 sqrt(x^3 + y^2))
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- e^(-x) sqrt(x^3 + y^2)) \
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& = (-3 x^2 y e^(-x))/2 dot (x^3 + y^2)^(-3/2)
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- (2 y e^(-x))/(2 sqrt(x^3 + y^2))
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$,
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$(dagger dagger)$,
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$
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& quad pdv(, x, y) e^(-x) sqrt(x^3 + y^2) \
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& = pdv(, x) space (-y e^(-x))/(sqrt(x^3 + y^2)) \
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& = (y e^(-x) sqrt(x^3 + y^2) + y e^(-x) dot 1 slash 2 dot (x^3
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+ y^2)^(-1/2)) / (x^3 + y^2) \
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& = (y e^(-x) (sqrt(x^3 + y^2) + 1 slash 2 dot (x^3
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+ y^2)^(-1/2))) / (x^3 + y^2)
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$,
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columns: 4,
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stroke: none,
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)
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],
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)
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]
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