59 lines
1.5 KiB
Python
59 lines
1.5 KiB
Python
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#!/usr/bin/env nix-shell
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#!nix-shell -i python3 -p python3
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# Hiding this really important number in an obscure piece of code is brilliant!
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# AND it's encrypted!
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# We want our biggest client to know his information is safe with us.
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bezos_cc_secret = "A:4@r%uL`M-^M0c0AbcM-MFE0g4dd`_cgN"
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# Reference alphabet
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alphabet = "!\"#$%&'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ"+ \
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"[\\]^_`abcdefghijklmnopqrstuvwxyz{|}~"
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def decode_secret(secret):
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"""ROT47 decode
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NOTE: encode and decode are the same operation in the ROT cipher family.
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"""
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# Encryption key
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rotate_const = 47
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# Storage for decoded secret
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decoded = ""
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# decode loop
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for c in secret:
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index = alphabet.find(c)
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original_index = (index + rotate_const) % len(alphabet)
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decoded = decoded + alphabet[original_index]
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print(decoded)
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def choose_greatest():
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"""Echo the largest of the two numbers given by the user to the program
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Warning: this function was written quickly and needs proper error handling
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"""
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user_value_1 = input("What's your first number? ")
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user_value_2 = input("What's your second number? ")
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greatest_value = user_value_1 # need a value to return if 1 & 2 are equal
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if user_value_1 > user_value_2:
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greatest_value = user_value_1
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elif user_value_1 < user_value_2:
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greatest_value = user_value_2
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print( "The number with largest positive magnitude is "
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+ str(greatest_value) )
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# NOTE: replaced function
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# choose_greatest()
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decode_secret(bezos_cc_secret)
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