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win32/build.py: build zlib in-tree 

zlib cannot be built out-of-tree, and previously, we were building in
the "src" directory, not in the "build" directory.  The
make_build_path() return value was unused.
This commit is contained in:
Max Kellermann 2015-06-03 07:35:25 +02:00
parent d6eb74262a
commit 6837a67234
1 changed files with 10 additions and 8 deletions
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18
win32/build.py
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@ -121,16 +121,20 @@ class Project:
except FileNotFoundError:
return False
def unpack(self):
global src_path
def unpack(self, out_of_tree=True):
global src_path, build_path
tarball = self.download()
path = os.path.join(src_path, self.base)
if out_of_tree:
parent_path = src_path
else:
parent_path = build_path
path = os.path.join(parent_path, self.base)
try:
shutil.rmtree(path)
except FileNotFoundError:
pass
os.makedirs(src_path, exist_ok=True)
subprocess.check_call(['/bin/tar', 'xfC', tarball, src_path])
os.makedirs(parent_path, exist_ok=True)
subprocess.check_call(['/bin/tar', 'xfC', tarball, parent_path])
return path
def make_build_path(self):
@ -189,9 +193,7 @@ class ZlibProject(Project):
Project.__init__(self, url, md5, installed, **kwargs)
def build(self):
src = self.unpack()
build = self.make_build_path()
src = self.unpack(out_of_tree=False)
select_toolchain()
subprocess.check_call(['/usr/bin/make', '--quiet',