diff --git a/Exercise 3/figures/3b.tex b/Exercise 3/figures/3b.tex new file mode 100644 index 0000000..3b2faf5 --- /dev/null +++ b/Exercise 3/figures/3b.tex @@ -0,0 +1,3 @@ +\begin{tikzpicture} + \draw (0,0) ellipse (2cm and 1cm); +\end{tikzpicture} \ No newline at end of file diff --git a/Exercise 3/figures/4a.tex b/Exercise 3/figures/4a.tex new file mode 100644 index 0000000..b71d02f --- /dev/null +++ b/Exercise 3/figures/4a.tex @@ -0,0 +1,34 @@ +\begin{tikzpicture}[ + my angle/.style={ + draw, <->, + angle eccentricity=1.3, + angle radius=9mm + } +] + +% coordinate axis +\draw[<->] (-2.5,0) -- (2.5,0); +\draw[<->] (0,-2.5) -- (0,2.5); + +% circle +\draw (0,0) circle (2cm); + +% coordinates +\coordinate (A) at ( 2,0); +\coordinate (B) at ( 0,2); +\coordinate (C) at (-2,0); +\coordinate (D) at (0,-2); + +% +\coordinate (O) at ( 0:0); + +\draw (C) node[anchor=north east] {-1}; + +% angles +\shorthandoff{"} +\pic[my angle, "$-\pi$"] {angle = C--O--A}; +\pic[my angle, "$\pi$"] {angle = A--O--C}; +\shorthandon{"} + +% \coordinate[pin=300:{$(0,-1)$}] (sinTheta) at (C); +\end{tikzpicture} \ No newline at end of file diff --git a/Exercise 3/main.pdf b/Exercise 3/main.pdf new file mode 100644 index 0000000..2be4ec9 Binary files /dev/null and b/Exercise 3/main.pdf differ diff --git a/Exercise 3/main.tex b/Exercise 3/main.tex new file mode 100644 index 0000000..04c012c --- /dev/null +++ b/Exercise 3/main.tex @@ -0,0 +1,45 @@ +\documentclass{article} + +\input{../lib/lib.tex} + +\begin{document} + + \thispagestyle{plain} + \tittel + \tableofcontents + + \newpage + + \section{Forberedende oppgaver} + \begin{oppgaver} + + \oppg + \input{tasks/1.tex} + + \oppg + \input{tasks/2.tex} + + \end{oppgaver} + + \newpage + + \section{Innleveringsoppgaver} + \begin{oppgaver} + + \setoppg{2} + + \oppg + \input{tasks/3.tex} + + \oppg + \input{tasks/4.tex} + + \oppg + \input{tasks/5.tex} + + \oppg + \input{tasks/6.tex} + + \end{oppgaver} + +\end{document} \ No newline at end of file diff --git a/Exercise 3/tasks/1.tex b/Exercise 3/tasks/1.tex new file mode 100644 index 0000000..ce5ccaf --- /dev/null +++ b/Exercise 3/tasks/1.tex @@ -0,0 +1,8 @@ +\renewcommand{\labelenumii}{\arabic{enumii}.} +\begin{enumerate} + \item \[ 100^{-\frac{1}{2}} = \frac{1}{100^\frac{1}{2}} = \frac{1}{\sqrt{100}} = \frac{1}{10} \] + \item \[2^{log_2\left(2020\right)} = 2020\] + \item \[ sin(-2020\pi) \rightarrow -2020 \bmod 1 = 0 \Leftrightarrow sin(-2020\pi) = 0\] + \item \[\sqrt{y^2} = \pm y \] + \item \[\left(\sqrt{y}\right)^2 = \left(y^{\frac{1}{2}}\right)^2 = y^\frac{1}{2} \cdot y^\frac{1}{2} = y^\frac{2}{2} = \sqrt{y^2} = \pm y \] +\end{enumerate} \ No newline at end of file diff --git a/Exercise 3/tasks/2.tex b/Exercise 3/tasks/2.tex new file mode 100644 index 0000000..535bc5f --- /dev/null +++ b/Exercise 3/tasks/2.tex @@ -0,0 +1,5 @@ +\[ \frac{1}{(x-0.5)(x+3)} \] + +Uttrykket er udefinert når nevneren blir 0 fordi man ikke kan dele på 0. + +Dette skjer ved $x \in \{-3, 0.5\}$ \ No newline at end of file diff --git a/Exercise 3/tasks/3.tex b/Exercise 3/tasks/3.tex new file mode 100644 index 0000000..be04095 --- /dev/null +++ b/Exercise 3/tasks/3.tex @@ -0,0 +1,33 @@ +\begin{deloppgaver} + \delo + \[ x^2 -6x +y^2 +2y +y = 0 \] + + Vi fullfører kvadratene + + \begin{align*} + x^2 -6x + 9 + y^2 +2y + 1 + 7 &= 0 + 9 + 1 \\ + \left(x-3\right)^2 + \left(y+1\right)^2 + 7 &= 10 \\ + \left(x-3\right)^2 + \left(y+1\right)^2 &= 3 \\ + \end{align*} + + Ettersom + + \begin{align*} + (x-x_0)^2 + (y-y_0)^2 = r^2 + \end{align*} + + vet vi at + + \[ S(3,-1) \text{ og } r=\sqrt{3} \] + + \delo + Vi ser at leddene $2y^2$ og $x^2$ har forskjellige koeffisienter. Dette betyr at etter de er faktorisert, så kommer de til å bli vektlagt forskjellig. Uttrykket representerer en ellipse hvor y-aksen har halvparten så stor variasjon som x-aksen + + \begin{minipage}{0.35\textwidth} + \begin{graphbox} + \input{figures/3b.tex} + \end{graphbox} + \end{minipage} + + +\end{deloppgaver} \ No newline at end of file diff --git a/Exercise 3/tasks/4.tex b/Exercise 3/tasks/4.tex new file mode 100644 index 0000000..c8a5147 --- /dev/null +++ b/Exercise 3/tasks/4.tex @@ -0,0 +1,46 @@ +\begin{deloppgaver} + \delo + \begin{align*} + cos(x) &= -1 \\ + x &= acos(-1) \\ + x &= \pm \pi + 2n\pi + \end{align*} + + \begin{minipage}{0.42\textwidth} + \begin{graphbox} + \input{figures/4a.tex} + \end{graphbox} + \end{minipage} + + + Ettersom forskjellen mellom $\pi$ og $-\pi$ er $2\pi$ som er et element i $2n\pi$, kan vi slå sammen svarene og si at + + \[ x = \pi + 2n\pi \] + + \delo + \[cos(2x)=1-2sin^2(x)\] + + Vi substituerer $cos(2x)=cos^2(x)-sin^2(x)$ og $cos^2(x)+sin^2(x)=1$ + + \begin{align*} + cos^2(x)-sin^2(x) &= cos^2(x)+sin^2(x) - 2sin^2(x) \\ + cos^2(x) &= cos^2(x)+2sin^2(x) - 2sin^2(x) \\ + cos^2(x) &= cos^2(x) + \end{align*} + + \delo + \[cos(\frac{\pi}{8})\] + + Vi bruker + + \[ sin(2a) = 2 sin(a)cos(a) \] + + Hvor $a = \frac{\pi}{8}$ + + \begin{align*} + sin\left(\frac{\pi}{4}\right) &= 2sin\left(\frac{\pi}{8}\right)cos\left(\frac{\pi}{8}\right) \\[1em] + cos\left(\frac{\pi}{8}\right) &= \frac{sin\left(\frac{\pi}{4}\right)}{2sin\left(\frac{\pi}{8}\right)} \\[1em] + &= \frac{\frac{1}{\sqrt{2}}}{2sin\left(\frac{\pi}{8}\right)} + \end{align*} + +\end{deloppgaver} \ No newline at end of file diff --git a/Exercise 3/tasks/5.tex b/Exercise 3/tasks/5.tex new file mode 100644 index 0000000..9c8d9ed --- /dev/null +++ b/Exercise 3/tasks/5.tex @@ -0,0 +1,15 @@ +\begin{align*} + x^2+2x+2 &> 50 \\ + (x+1)^2 + 1 &> 50 \qquad \text{(første kv. setning)} \\ + (x+1)^2 &> 49 \\ + x+1 &> \pm\sqrt{49} \\ +\end{align*} + +Vi deler opp likningen + +\begin{align*} + -\sqrt{49} &< x+1 &&\vee& x+1 &< \sqrt{49} \\ + -7 &< x+1 &&\vee& x+1 &< 7 \\ + -8 &< x &&\vee& x &< 6 \\ +\end{align*} +\[x \in \left(-8,6\right)\] \ No newline at end of file diff --git a/Exercise 3/tasks/6.tex b/Exercise 3/tasks/6.tex new file mode 100644 index 0000000..ef34d7f --- /dev/null +++ b/Exercise 3/tasks/6.tex @@ -0,0 +1,7 @@ +\begin{deloppgaver} + \delo + I informatikk så har vi en lov som kalles Moore's lov. Den sier at hvert andre år, vil antall transistorer vi kan plassere på et visst areal være det dobbelte i forhold til to år tidligere. Ettersom dette vil vokse med (og har vokst med) eksponsensiell fart, vil det gi mening å plassere det på en logaritmisk skala. I dette tilfellet, $y = log_2(x)$ + + \delo + Der hvor en vanlig skala som viser en tallrekke fra 1 til 9 faktisk betyr 1 til 9 av en spesifikk enhet, vil en logaritmisk skala stige eksponsensielt fra 1 til 9. Differansen mellom 1 og 2 er forskjellig fra differansen mellom 2 og 3. Om vi tar $log_{10}$ spesifikt, så vil forskjellen fra 1 til 2 være 10, mens 2 til 3 er 10 til 100. Tallrekken viser $log_{10}(x)$ hvor x er den faktiske verdien. +\end{deloppgaver} \ No newline at end of file diff --git a/lib/lib.tex b/lib/lib.tex index d5627f3..d68cb0e 100644 --- a/lib/lib.tex +++ b/lib/lib.tex @@ -26,7 +26,7 @@ \pgfplotsset{compat=newest} \author{Øystein Tveit} -\title{MA0001 Øving 2} +\title{MA0001 Øving 3} \input{../lib/titling.tex}